# Line slope calculator 3x-5y=-3

**Straight line given by points A[4; 3] and B[9; 6]**

## Calculation:

**Slope-intercept form of line:**y = 0.6x+0.6

**Canonical form of the line equation:**3x-5y+3 = 0

**Parametric form of the line equation:**

x = 5t+4

y = 3t+3 ; t ∈ R

**Slope:**m = 0.6

**Slope angle of line: φ =**30°57'50″ = 0.5404 rad

**X intercept:**x

_{0}= -1

**Y intercept:**y

_{0}= q = 0.6

**Distance line from the origin:**d

_{0}= 0.5145

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(5; 3)

**Normal vector: n =**(3; -5)

**Midpoint of the segment AB: M =**[6.5; 4.5]

**Perpendicular Bisector equation:**5x+3y-46 = 0

**Vector OA = (4; 3) ; |OA| = 5**

**Vector OB = (9; 6) ; |OB| = 10.8167**

**Scalar product OA .OB = 54**

**Angle ∠ AOB = 3°10'47″ = 0.0555 rad**